Question

Find all possible values of $\sqrt{x^2+25}$

• A. [0, ∞)
• B. (0, ∞)
• C. [5, ∞)
• D. [25, ∞)

Answer 1

The correct option is C

[5, ∞)

We know that $x^2$ ≥ 0

$x^2$ + 25 ≥ 25

Minimum value of square root of 25 is 5, when x = 0

So, $\sqrt{x^2+25}$ ∈ [5,$\infty$)