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Question

Find all possible values of x for which the distance between the points

A (x, -1) and B (5, 3) is 5 units.

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Solution

We know that the distance between two points (x1,y1) and (x2,y2) ,

d=(x2x1)2+(y2y1)2

Given d = 5 units and points are A (x, -1) and B (5, 3)

(5x)2+(31)2=5

(5x)2+(3+1)2=25

(5x)2+16=25

(5x)2=2516

(5x)2=9

(5x)=9

(5x)=±3

x=5±3

x=5+3 or 53

x=8 or 2


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