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Question

Find all real numbers x which satisfy the equation 2log2log2x+log1/2log2(22x)=1.

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Solution

Given 2log2log2x+log1/2log2(22x)=1
Let log2x=y

2log2y+log21(log223/2+y)=1
log2y2log2(y+32)=1
y2y+32=2
y22y3=0
y=3,1
log2x=3,1
x=8,12

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