Question

Find all the angles of an equilateral triangle.

• A. ${60}^0,{60}^0,{60}^0$
• B. ${90}^0,{30}^0,{60}^0$
• C. ${90}^0,{45}^0,{45}^0$
• D. ${120}^0,{30}^0,{30}^0$

Answer 1

The correct option is A ${60}^0,{60}^0,{60}^0$

Given, $△ABC$ is an equilateral triangle. In an equilateral triangle all the angles are equal.
$\angle A=\angle B=\angle C=x$
Sum of angles = 180
$\angle A+\angle B+\angle C=180$
$x+x+x=180$
$x=60$
Thus, $\angle A=\angle B=\angle C={60}^{\circ }$