Find all the common zeroes of the polynomials x3+5x2−9x−45 and x3+8x2+15x.
Let:
P(x)=x3+5x2−9x−45 ; Q(x)=x3+8x2+15x
P(x)=x2(x+5)−9(x+5)
P(x)=(x+5)(x2−9)
P(x)=(x+5)(x+3)(x−3)
⇒ Zeroes of x3+5x2−9x−45 are -5,-3 and 3.
Q(x)=x(x2+8x+15)
Q(x)=x(x+5)(x+3)
⇒ Zeroes of x3+8x2+15x are 0,-5 and -3.
∴ common zeroes are -5 and -3.