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Question

Find all the zeroes of the polynomial 2x411x3+7x2+13x7 .It being given two of its zeroes are (3+2) and (32).

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Solution

Let α and β be zeroes of polynomial
α=3+2 and β=32
α+β=6 and αβ=7
x26x+7
Given polynomial is 2x411x3+7x2+13x7
x26x+7)2x411x3+7x2+13x7(2x2+x1
2x412x3+14x2
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x37x2+13x7
x36x2+7x
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x2+6x7
x2+6x+7
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0
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The Quotient is 2x2+x1
=2x2+2xx1
=2x(x+1)1(x+1)
=(2x1)(x+1)
x=12,1 are the other zeros of the polynomial.

1225149_1501935_ans_cfd67b0d6a6747d989dca6ea182f5d02.jpeg

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