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Question

Find all the zeroes of the polynomial 3x4+6x32x210x5, if two of its zeroes are 53 53.

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Solution

P(x)=3x4+6x32x210x5
as we have given that two of its zeros are 5/3 and 5/3, so their factors are (x5/3) and (x+5/3)
The product of the factors;
(x5/3).(x+5/3)=x25/3
=3x25/3=13(3x25)
Now g(x)=3x25
dividing p(x) by g(x) we get
q(x)=x2+2x+1
by division algorithm
p(x)=g(x)+q(x)+r(x)
=(3x25)(x2+2x+1)
=(3x25)(x2+x+x+1)
=(3x25)(x(x+1)+1(x+1))
=(3x25)(x+1)(x+1)
The other two zeros are -1 and -1

1201495_1413467_ans_e771b87c22904fffa1915eb6087a8d46.jpg

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