Question

Find all the zeros of $x^3+6x^2+11x+6$ if $(x+1)$ is a factor.

Answer 1

Since $(x+1)$ is a factor of given cubic equation.

$\therefore$ it will completely divide the given equation.

Now, $(x^3+6x^2+11x+6)=(x^2+5x+6)(x+1)$

$=(x+2)(x+3)(x+1)$

$\therefore$ zeros of $(x+1)(x+2)(x+3)=0$ are

$x+1=0\Rightarrow x=-1$

$x+2=0\Rightarrow x=-2$

$x+3=0\Rightarrow x=-3$