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Kepler's Law

Find an expre...

Question

Find an expression for the electric field at $r < a$

\frac{k_{e} q}{r^{2}} (-^r)

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\frac{k_{e} q}{r^{2}}^r

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\frac{2 k_{e} q}{r^{2}} (-^r)

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\frac{2 k_{e} q}{r^{2}}^r

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Solution

The correct option is D $\frac{2 k_{e} q}{r^{2}}^r$
Inner radius $= a$
outer radius $= b$
conductor is hollow $(r < a)$
charge $= 2 Q$
$ϕ_{A} =$ Using Gauss's law
$= E A = \frac{Q}{ϵ_{0}} = \frac{2 k_{e} q}{r^{2}} ({- r}^{T})$

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