Find and correct the errors in the following mathematical statements:

i.)Substituting x= -4 in $x^{2}$ +6x+4 gives $(- 4)^{2}$ ;+ 6(-4) + 4 = 16-24+4 = -4

ii.) 3x/(3x+2) = ½

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Solution

i.)True. There is no error. Substituting x= -4 in $x^{2}$ +6x+4 gives $(- 4)^{2}$ + 6(-4) + 4 = 16-24+4 = -4

ii.) 3x/(3x+2) = ½ is not correct.

3x in numerator and denominator will not cancel out. So, we need the value of x to get the value of the expression.

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Similar questions

Q. Find and correct errors of the following mathematical expressions:ind and correct error

(3 x + 2)^{2} = 3 x^{2} + 6 x + 4

Q. Find and correct error in the following mathematical statement.
Substituting

x = - 3

in:
(a)

x^{2} + 5 x + 4

gives

(- 3)^{2} + 5 (- 3) + 4 = 9 + 2 + 4 = 15

(b)

x^{2} - 5 x + 4

gives

(- 3)^{2} - 5 (- 3) + 4 = 9 - 15 + 4 = - 2

(c)

x^{2} + 5 x

gives

(- 3)^{2} + 5 (- 3) = - 9 - 15 = - 24

Find and correct the errors in the following mathematical statement, Substituting $x = - 3$ in
$x^{2} + 5 x + 4$ gives $(- 3)^{2} + 5 (- 3) + 4 = 9 + 2 + 4 = 15$

Question 10(ii)
Find and correct the errors in the following mathematical statement. Substituting $x = - 3$ in
$x^{2} - 5 x + 4 g i v e s (- 3)^{2} - 5 (- 3) = 9 - 15 + 4 = - 2$

Find and correct the errors in the following mathematical statement. Substituting x = −3 in

(a) x² + 5x + 4 gives (−3)² + 5 (−3) + 4 = 9 + 2 + 4 = 15

(b) x² − 5x + 4 gives (−3)² − 5 (−3) + 4 = 9 − 15 + 4 = −2

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Find and correct the errors in the following mathematical statements: i.)Substituting x= -4 in x2+6x+4 gives (−4)2;+ 6(-4) + 4 = 16-24+4 = -4 ii.) 3x/(3x+2) = ½

i.)True. There is no error. Substituting x= -4 in x2+6x+4 gives (−4)2+ 6(-4) + 4 = 16-24+4 = -4 ii.) 3x/(3x+2) = ½ is not correct. 3x in numerator and denominator will not cancel out. So, we need the value of x to get the value of the expression.

Find and correct the errors in the following mathematical statements:

i.)Substituting x= -4 in $x^{2}$ +6x+4 gives $(- 4)^{2}$ ;+ 6(-4) + 4 = 16-24+4 = -4

ii.) 3x/(3x+2) = ½

i.)True. There is no error. Substituting x= -4 in $x^{2}$ +6x+4 gives $(- 4)^{2}$ + 6(-4) + 4 = 16-24+4 = -4

ii.) 3x/(3x+2) = ½ is not correct.

3x in numerator and denominator will not cancel out. So, we need the value of x to get the value of the expression.