Question

Find and correct the errors in the mathematical statement $\left(a-4\right)\left(a-2\right)=a^2-8$

Answer 1

Verify if the mathematical statement holds true and make appropriate changes where necessary

$\therefore$ L.H.S$=$$\left(a-4\right)\left(a-2\right)$

$\Rightarrow$ $=a^2-4a-2a+8$

$\Rightarrow$L.H.S$=a^2-6a+8$

But R.H.S$=$$a^2-8$

Hence, L.H.S$\ne$R.H.S

$-6a$ is missing in RHS

The correct mathematical statement is $\left(a-4\right)\left(a-2\right)=a^2-6a+8$.