Find and correct the errors in the statement: (2x)² + 4(2x) + 7 = 2x² + 8x + 7

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Solution

L.H.S = (2x)² + 4(2x) + 7 = 4x² + 8x + 7 ≠ R.H.S

The correct statement is (2x)² + 4(2x) + 7 = 4x² + 8x + 7

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Similar questions

(2 x)^{2} + 4 (2 x) + 7 = 2 x^{2} + 8 x + 7

(2 x)^{2} + 4 (2 x) + 7 = 2 x^{2} + 8 x + 7

(2 x)^{2} + 4 (2 x) + 7 = 2 x^{2} + 8 x + 7

{(2 x)}^{2} + 4 (2 x) + 7 = 3 x^{2} + 8 x + 7 5 y + 2 y + y - 7 y = 0

(2 x)^{2} + 4 (2 x) + 7 = M x^{2} + 8 x + 7

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