Find $∠ A$ in $△ A B C$ in which $∠ B = 60, ∠ C = 45^{o}$

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Solution

The angles are $∠ B = 60^{\circ}, ∠ C = 45^{\circ}$
In triangle all angles sum up to give $180^{\circ}$
$∠ A + ∠ B + ∠ C = 180^{\circ} ∠ A + 60 + 45 = 180 ∠ A = 180 - 105 ∠ A = 75^{\circ}$

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Similar questions

△ A B C

∠ B = 60^{o}, ∠ C = 45^{o}

∠ A

△ A B C, ∠ B = 90^{o}, ∠ A = 45^{o} = ∠ C

sec 45^{o} =

△ A B C, ∠ A = \frac{2 π^{c}}{3}

∠ B = 45^{o}

∠ C

△ A B C, m ∠ A = {\frac{2 π}{3}}^{c}

m ∠ B = 45^{o}

m ∠ C

∠ B = ∠ C = 45^{o}

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