In the figure given below, if OP || RS, ∠OPQ=110o and ∠QRS=130o, then ∠PQR is equal to:
In the figure given below, if OP || RS, ∠OPQ = 110o and ∠QRS = 130o, then ∠PQR is equal to
Construct a triangle PQR, in which ∠P = 30°, ∠Q = 45° and PQ + QR + RP = 22 cm. [4 MARKS]