The correct option is C 1.91 We know that AntiLog(x)=10^x ⇒ AntiLog(0.2817)=10^0.2817=1.91 This exact value should be find by using anti logarit ...

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Conditions on the Domain and the Range of the Logarithmic Function

Find AntiLo...

Question

Find $A n t i L o g (.2817)$ .

1.70

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2.19

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1.91

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1.99

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Solution

The correct option is C $1.91$
We know that $A n t i L o g (x) = 10^{x}$
$\Rightarrow A n t i L o g (0.2817) = 10^{0.2817} = 1.91$
This exact value should be find by using anti logarithm table.
Therefore the correct option is $C$

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