Question

Find any ten rational numbers between $\frac{-5}{6}$ and $\frac{5}{8}$.

Answer 1

Making their denominators same = $\frac{-5\times 8}{6\times 8}=\frac{-40}{48}$ and $\frac{5\times 6}{8\times 6}=\frac{30}{48}$
We can pick any ten integers as numerator in between $-40$ and $30$ with denominator as $48$ :
$(\frac{-35}{48},\frac{-31}{48},\frac{-7}{48},\frac{-23}{48},\frac{9}{48},\frac{1}{48},\frac{19}{48},0,\frac{27}{48},\frac{24}{48}=\frac{1}{2})$