Question

Find any two solutions of the linear equation : $3x-3y=9$

Answer 1

Let $x=0;$
Then $3\left(0\right)-3y=9;$
$-3y=9$
$y=\frac{-9}{3}$
So one solution will be $x=0;y=-3$
Let $y=0;$
Then $3\left(x\right)-3\left(0\right)=9;$
$3x=9$
$x=\frac{9}{3}$
Other solution will be $x=3;y=0$