Question

Find area of parallelogram $ABCD$ if $AB=8cm,BC=4cm$ and distance between the two parallel lines $AB$ and $CD$ is $3cm$. Find the distance between $AD$ and $BC$.

Answer 1

Given, $AB=8cm;BC=4cm$

Perpendicular distance between $AB$ and $BC$ is $DL=3cm$

The area of the parallelogram $=base\times height$
$=AB\times DL$

$=8\times 3=24c{m}^2$

Area of the parallelogram $=base\times height$

$=AD\times BM$

$24=4\times height$

$Height=6cm$

So the perpendicular distance between $AD$ and $BC$ is $6cm$