Question

Find area of quadrilateral ABCD

Answer 1

Given,
Length of diagonal = d = 10 cm
Length of Perpendicular dropped on AC
$h_1=5cm\&h_2=3cm$
Now,
Area of ABCD = $\frac{d}{2}\times (h_1+h_2)=\frac{10}{2}\times (5+3)=\frac{10}{2}\times (5+3)=5\times 8=40c{m}^2$
Area of quadrilateral = $40c{m}^2$.