Question

Find area of region lying in first quadrant and bounded by $x^{2}16y,y=1,=y=4$ and y-axis.

Answer 1

$\begin{array}{c}\int xdy={\int }_1^{4}4y^{1/2}dy\\ {\left[2\times \frac{4-y^{3/2}}{3}\right]}_1^4=\frac{8}{3}\left[8-1\right]\\ =\frac{56}{2}\end{array}$