Question

Find area of the shape obtained when a semicircle is being attached with the square of side $5$ cm,such that semicircle lies outside the square.

• A. $64.28c{m}^2$
• B. $54.26c{m}^2$
• C. $44.26c{m}^2$
• D. $40.26c{m}^2$

Answer 1

The correct option is A $64.28c{m}^2$

Area of shape obtained=Area of square$+4\times$ area of semi circle

$=(5\times 5)+4\times \frac{1}{2}\times \frac{22}{7}\times 2.5\times 2.5$

$=25+39.28$

$=64.28$ sq. cm