Question

Find area of triangle whose base is $40$ cm and altitude is $80$ cm.

• A. $160{cm}^2$
• B. $1600{cm}^2$
• C. $100{cm}^2$
• D. $16{cm}^2$

Answer 1

The correct option is B $1600{cm}^2$

Area of triangle $=\frac{1}{2}\times b\times h$

$b=40cm,h=80cm$

$\therefore A=\frac{1}{2}\times 40\times 80{cm}^2$

$=1600{cm}^2$