wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find arithmetic mean of the following frequency distribution by step deviation method.
Variate51015202530frequency204375677245


A
19.09
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
20.09
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
30.09
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12.09
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 19.09

1.Choose an arbitrary constant 'a'. (also called assumed mean)

2. xi = Upper limit+Lower limit2

3. Subtract the value of 'a' from xi.

4. The reduced value of (xia) is called the deviation of xi from 'a'.

5. Divide the deviation by constant where 'h' is the width of the class interval.

6. ui=xiah

Let the assumed mean be a = 20 and h = 5

VariatefrequencyDeviationui=(xi20)5fiui (xi) (fi)di=xi20 5201536010431028615755175206700025725172304510290 N=fi=322 fiui=59

Here,
N=322,a=20,h=5 and fiui=59

Mean=a+fiuif×h
Mean=20+(59322)5
=200.91
=19.09


flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mean
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon