The correct option is
A 7.2In
△ACE and
△BCD,
∠ACE=∠BCD (Common angle)
∠CBD=∠CAE (Corresponding angles, since
BD||AE)
∠CDB=∠CEA (Corresponding angles, since
BD||AE)
Hence,
△ACE∼△BCD.
Thus,
BCAC=CDCE⟹ BCBC+AB=CDCD+DE (Given,
CD=DE)
⟹ BCBC+AB=12⟹ 2BC=AB+BC⟹ BC=AB ⟹ BC=7.2cm.
Hence, option A is correct.