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\frac{k ϵ_{0} A}{d}

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\frac{ϵ_{0} A}{d} (\frac{k + 1}{k})

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\frac{ϵ_{0} A}{d} (\frac{2 k + 1}{k + 1})

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\frac{ϵ_{0} A}{2 d} (\frac{3 k + 1}{k + 1})

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Solution

The correct option is D $\frac{ϵ_{0} A}{2 d} (\frac{3 k + 1}{k + 1})$

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