Find -38-711A -1988B -1188C -1811D -11388

38 711= 3×118×11 7×811×8= 33 5611×8 = 8988= 1188 So, option B is correct answer. nbsp; ...

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Intersection of Sets

Find -38-711A...

Question

Find $\frac{- 3}{8} - \frac{7}{11}$
(A) $- 1 \frac{9}{88}$
(B) $- 1 \frac{1}{88}$
(C) $- 1 \frac{8}{11}$
(D) $- 1 \frac{13}{88}$

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7 + 10 \frac{1}{2} + 14 + . . . + 84

18 + 15 \frac{1}{2} + 13 + . . . + (- 49 \frac{1}{2})

Use the sign of >, < or = in the box to make the statements true.

Fill in the blanks.

(i) $(\frac{- 3}{17}) + (\frac{- 12}{5}) = (\frac{- 12}{5}) + (. . . . .)$

(ii) $- 9 + \frac{- 21}{8} = (. . . . . .) + (- 9)$

(iii) $(\frac{- 8}{13} + \frac{3}{7}) + (\frac{- 13}{4}) = (. . . . . .) + [\frac{3}{7} + (\frac{- 13}{4})]$

(iv) $- 12 + (\frac{7}{12} + \frac{- 9}{11}) = (- 12 + \frac{7}{12}) + (. . . . .)$

(v) $\frac{19}{- 5} + (\frac{- 3}{11} + \frac{- 7}{8}) = {\frac{19}{- 5} + (. . . . .)} + \frac{- 7}{8}$

(vi) $\frac{- 16}{7} + . . . . . = . . . . . . + \frac{- 16}{7} = \frac{- 16}{7}$

\frac{5}{7} + \frac{9}{11} = \frac{118}{11 a}

a

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