613 ( 715 ) = 6 ×1513×15 ( 7× 1315 × 13 ) nbsp;[L.C.M of 13 and 15 is 195] nbsp; = 90195 ( 91195 ) nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; ...

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Byju's Answer

Standard V

Mathematics

Multiplication of Numbers

Find:-613- -7...

Question

Find:
$\frac{- 6}{13} - (\frac{- 7}{15})$

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Solution

$\frac{- 6}{13} - (\frac{- 7}{15}) = \frac{- 6 \times 15}{13 \times 15} - (\frac{- 7 \times 13}{15 \times 13}) [L.C.M of 13 and 15 is 195] = \frac{- 90}{195} - (\frac{- 91}{195})$
$= \frac{- 90 - (- 91)}{195} = \frac{- 90 + 91}{195} = \frac{1}{195}$

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Similar questions

Q. Find :

\frac{- 6}{13} \div \frac{- 7}{15}

Question 2 (iii)

Find:
$\frac{- 6}{13} - (\frac{- 7}{15})$

Q. Find the median of the following data.

$x$	$5$	$6$	$10$	$12$	$13$	$15$
$f$	$7$	$8$	$15$	$13$	$9$	$8$

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Q. Find the missing term (denoted by question mark '?')

6	7	4	15
7	15	25	28
8	13	?	20
3	5	7	9

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Find: −613−(−715)

−613−(−715)=−6×1513×15−(−7×1315×13)[L.C.M of 13 and 15 is 195]=−90195−(−91195) =−90−(−91)195=−90+91195=1195

Find:
$\frac{- 6}{13} - (\frac{- 7}{15})$

$\frac{- 6}{13} - (\frac{- 7}{15}) = \frac{- 6 \times 15}{13 \times 15} - (\frac{- 7 \times 13}{15 \times 13}) [L.C.M of 13 and 15 is 195] = \frac{- 90}{195} - (\frac{- 91}{195})$
$= \frac{- 90 - (- 91)}{195} = \frac{- 90 + 91}{195} = \frac{1}{195}$