Find. $\frac{cosec 40^{0}}{sec 40^{0}}$

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Solution

Given, $\frac{cosec 40^{0}}{sec 40^{0}}$

$= \frac{\frac{1}{sin 40^{0}}}{\frac{1}{cos 40^{0}}}$

$= \frac{cos 40^{0}}{sin 40^{0}}$

$= cot 40^{0}$

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