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Byju's Answer
Standard IX
Mathematics
Experimental/Empirical Probability
Find chances ...
Question
Find chances of getting a sum of 9 atleast twice in ten throws with two dices.
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Solution
n
(
s
)
=
number of element in throw of two dice
=
6
×
6
=
36
n
=
10
P
=
success=getting sum
9
s
u
m
9
occurs in cases
on
(
4
,
5
)
,
(
5
,
4
)
,
(
3
,
6
)
,
(
6
,
3
)
∴
p
=
4
36
=
1
9
q
=
1
−
p
=
1
−
1
9
=
8
9
x
=no of success
∴
required probability
=
P
(
x
≥
z
)
=
1
−
p
(
x
=
0
)
−
p
(
x
=
1
)
=
1
−
10
C
0
(
1
9
)
0
(
8
9
)
10
−
10
C
1
(
1
9
)
1
(
8
9
)
9
=
1
−
1
×
1
×
8
10
9
10
−
10
×
1
9
×
8
9
9
9
=
1
−
(
8
9
)
10
−
10
×
8
9
9
10
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