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Question

Find charge on positive plate of 8 μF (assuming before connecting to battery all capacitors were uncharged)

A
36 μC
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B
12 μC
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C
24 μC
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D
6 μC
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Solution

The correct option is C 24 μC
Let s represent series and p represent parallel then to calculate effective capacitance, circuit can be represented by {12μF}(s){8μF(p)40μF}
which is equivalent to {12μF}(s){12μF}
=6μF
qsupplied=Ceff.ΔV=6×6=36μC
Now on 8μF& 4μF charge distributes propotional to their capacitance. Then charge on 8 μF capacitor is given by
q=412×36=24μC

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