Find conjugate: $- i (9 + 6 i) {(2 - i)}^{- 1}$

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Solution

$- i (9 + 6 i) (2 - i)^{- 1} = \frac{- 9 i + 6}{2 - i} = \frac{(6 - 9 i) (2 + i)}{5} = \frac{1}{5} (12 - 18 i + 6 i + 9) = \frac{1}{5} (21 - 12 i)$
The conjugate of $- i (9 + 6 i) (2 - i)^{- 1}$ is $\frac{1}{5} (21 + 12 i)$

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Find conjugate: −i(9+6i)(2−i)−1

−i(9+6i)(2−i)−1=−9i+62−i=(6−9i)(2+i)5=15(12−18i+6i+9)=15(21−12i)The conjugate of −i(9+6i)(2−i)−1 is 15(21+12i)

Find conjugate: $- i (9 + 6 i) {(2 - i)}^{- 1}$

$- i (9 + 6 i) (2 - i)^{- 1} = \frac{- 9 i + 6}{2 - i} = \frac{(6 - 9 i) (2 + i)}{5} = \frac{1}{5} (12 - 18 i + 6 i + 9) = \frac{1}{5} (21 - 12 i)$
The conjugate of $- i (9 + 6 i) (2 - i)^{- 1}$ is $\frac{1}{5} (21 + 12 i)$