Question

Find critical angle for glass and water pair, given refractive index of glass is $1.62$ and that of water is $1.33$.

Answer 1

using the snale's law

critical angle =${\theta }_1$, $n_g=1.62$, $n_w=1.33$,${\theta }_2={90}^{\circ }$

$\Rightarrow n_g\sin {\theta }_1=n_w\sin {\theta }_2$

$\Rightarrow \sin {\theta }_1=\frac{1.33}{1.62}\times 1$

$\Rightarrow {\theta }_1={55.18}^{\circ }$