Question

Find derivative of $\sqrt[2]{2sin2x}$

Answer 1

$\frac{d\left(\sqrt{sin2x}\right)}{dx}=\frac{1}{2\sqrt{sin}}\frac{d\left(sin2x\right)}{dx}\frac{d\left(2x\right)}{dx}$ [ Chain rule of differentiation]
$=\frac{1}{2\sqrt{sinx}}cos\left(2x\right)\times 2$
$=\frac{cos2x}{sin2x}$