Find 124- 148- 1816- 11632

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Standard VI

Mathematics

Exponents with Unlike Bases and Same Exponent

Find 124, 1...

Question

Find $\frac{1}{2^{4}}, \frac{1}{4^{8}}, \frac{1}{8^{16}}, \frac{1}{16^{32}}$

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Solution

In the series,
The base in the denominator is in GP with $a = 2, r = 2$
The exponent in the denominator is alos in GP with $a = 4, r = 2$
So the $n^{t h}$ Term is given $\frac{1}{(2 (2)^{n - 1})^{4 (2)^{n - 1}}}$

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Find 124,148,1816,11632

In the series,The base in the denominator is in GP with a=2,r=2The exponent in the denominator is alos in GP with a=4,r=2So the nth Term is given 1(2(2)n−1)4(2)n−1

Find $\frac{1}{2^{4}}, \frac{1}{4^{8}}, \frac{1}{8^{16}}, \frac{1}{16^{32}}$

In the series,
The base in the denominator is in GP with $a = 2, r = 2$
The exponent in the denominator is alos in GP with $a = 4, r = 2$
So the $n^{t h}$ Term is given $\frac{1}{(2 (2)^{n - 1})^{4 (2)^{n - 1}}}$