Find $\frac{1}{2} x (1 + 1 \cdot 2)$ .

Open in App

Solution

$\frac{1}{2} x (1 + 1 \cdot 2)$
$= \frac{1}{2} x (1 + 2) = \frac{3 x}{2}$

Suggest Corrections

Similar questions

The anti derivative of equals

(A) (B)

f (x) = x^{\frac{1}{2}} + 8 x^{\frac{1}{3}} - \frac{1}{2} x^{\frac{1}{4}}

x^{n}

\frac{(1 + x) (1 + 2 x) (1 + 3 x)}{(1 - x) (1 - 2 x) (1 - 3 x)}

x

{(2 x^{1 / 2} - \frac{x^{- 1 / 3}}{3})}^{20}

lim x \to 0 \frac{(1 + x) (x + 2 x) (1 + 3 x) - 1}{x} .

Join BYJU'S Learning Program