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Question

Find ddx(cos2x) by using chain rule.

A
sin2x
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B
cos2x
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C
(1+cosx)
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D
2sin2x
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Solution

The correct option is D sin2x

Differentiatingbychainrule (d(cosx)2d(cosx))×(dcosxdx)=2cosx×(sinx)=2sinxcosx=sin2x


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