Question

Find $\frac{dy}{dx}$ for $y=\sin x^o$.

Answer 1

Given,

$y=\sin x^o$

or, $y=\sin \frac{x\pi }{{180}^o}$

Now differentiating both sides with respect to $x$ we get,

$\frac{dy}{dx}=\frac{\pi }{{180}^o}\cos \frac{x\pi }{{180}^o}$

or, $\frac{dy}{dx}=\frac{\pi }{{180}^o}\cos x^o.$