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Question

Find dydx if y=sec1[12x21], 0<x>12

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Solution

y=sec1(12x21)
x=cosθ
2x21=2cos2θ1=cos2θ
y=sec1(1cos2θ)
y=sec1(sec2θ)=2θ=2cos1x
dydx=21x2
Hence, dydx=21cos2θ

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