Question

Find $\frac{dy}{dx}$, if $y=(x^3-2)x$.

• A. $4x^3-2x$
• B. $4x^2-2x$
• C. $3x^4-2$
• D. $4x^3-2$

Answer 1

The correct option is D $4x^3-2$

We have,
$y=(x^3-2)x$
$y=x^4-2x$

$\therefore \frac{dy}{dx}=4x^{4-1}-2x^{1-1}$
$\frac{dy}{dx}=4x^3-2x^0$
$\frac{dy}{dx}=4x^3-2$