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Question

Find dydx of the equation :
y=1+2x+3x2+(n1)xn2

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Solution

Consider the given equation

y=1+2x+3x2+(n1)n2

Differentiate Bothe side with respect to x, we get

ddxy=ddx(1+2x+3x2+(n1)n2xn2)

=0+2+6x+(n1)(n2)xn3

dydx=2+6x+(n1)(n2)xn3



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