Question

Find$\frac{dy}{dx}$ of $y=\sin \left(logx\right)$ ?

Answer 1

Let,$y=sin\left(logx\right)$

Now Differentiate $y$ with respect to $x$

then $\frac{dy}{dx}=\frac{d}{dxsin\left(logx\right)}$

$\frac{dy}{dx}=\frac{cos\left(logx\right).d}{dx\left(logx\right)}$

$\frac{dy}{dx}=cos\left(logx\right).\frac{1}{x}$

So,the answer is $cos\left(logx\right).\left(\frac{1}{x}\right)$