Question

Find $\frac{dy}{dx}$ of $y=\tan x^2$.

• A. $4x{\sec }^2{x}^2$
• B. $2x{\tan }^2{x}^2$
• C. $2x{\sec }^{2}x$
• D. $2x{\sec }^2{x}^2$

Answer 1

The correct option is D $2x{\sec }^2{x}^2$

Using chain rule:
$\frac{d}{dx}\tan x^2={\sec }^2{x}^2.\left(2x\right)\frac{dy}{dx}=2x{\sec }^2{x}^2$