Find dydx - y-3x-5x2-log x - x

y+3x+5x^2=log x + x dydx+3+10x=1x+ x tan x dydx= x tan x +1x 10x 3 ...

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Logarithmic Differentiation

Find dydx :...

Question

Find $\frac{d y}{d x}$ :
$y + 3 x + 5 x^{2} = log x + sec x$

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Solution

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\frac{d y}{d x}

3 x^{2} + log x = y

y = (l o g x)^{x} + x^{x cos x}

\frac{d y}{d x}

\frac{d y}{d x}

y = e^{x} + u^{x} - log x

\frac{d y}{d x} + \frac{y}{x} = \frac{1}{{(1 + log x + log y)}^{2}}

x^{y} = e^{x - y}

\frac{d y}{d x} = \frac{l o g x}{(1 - l o g x)^{2}}

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