Question

Find $\frac{dy}{dx}$:

$y=e^{(1+{\log }_{e}x)}$.

Answer 1

Given,

$y=e^{(1+{\log }_{e}x)}$

or, $y=e.e^{{\log }_{e}x}$

or, $y=e.x$

Now, differentiating both sides with respect to $x$ we get,

$\frac{dy}{dx}=e$.