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Question

Find dydx :

y=sin(1+x21x2)

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Solution

y=sin(1+x21x2)

dydx=cos(1+x21x2)ddx(1+x21x2)

dydx=cos(1+x21x2)[(1x2)ddx(1+x2)(1+x2)ddx(1x2)(1x2)2]

dydx=cos(1+x21x2)[(1x2)×2x(1+x2)×(2x)(1x2)2]

dydx=cos(1+x21x2)4x(1x2)2

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