Question

Find

$\frac{{\sin }^2\theta +1-{\cos }^2\theta }{{\sin }^2\theta }$

Answer 1

$\frac{{\sin }^2\theta +1-{\cos }^2\theta }{{\sin }^2\theta }\frac{{\sin }^2\theta +{\sin }^2\theta +{\cos }^2\theta -{\cos }^2\theta }{{\sin }^2\theta }\frac{2{\sin }^2\theta }{{\sin }^2\theta }=2$