Question

Find $\frac{x}{y}$
if ${\left(\frac{3}{5}\right)}^{-4}\times {\left(\frac{15}{10}\right)}^{-4}={\left(\frac{x}{y}\right)}^{-4}$

Answer 1

Given equation

${\left(\frac{3}{5}\right)}^{-4}\times {\left(\frac{15}{10}\right)}^{-4}={\left(\frac{x}{y}\right)}^{-4}$

${[\frac{3}{5}\times \frac{15}{10}]}^{-4}={\left[\frac{x}{y}\right]}^{-4}$

$\frac{45}{50}=\frac{x}{y}$

$\frac{9}{10}=\frac{x}{y}$.