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Question

Find ex(1+ex)(2+ex)dx

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Solution

This can be solved using partial fractions and substitution.
Substitute ex=t.exdx=dt
Integral becomes 1(1+t)(2+t)dt
Using partial fractions,
1(1+t)(2+t)=2(1+t)(2+t)(1+t)(2+t)=22+t11+t
22+tdt=2ln|t+2|
11+tdt=ln|t+1|
1(1+t)(2+t)dt=2ln|t+2|ln|t+1|+c


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