Find - -sin tan-1x1 - x2 dx- x - R

Let #160; I = ∫sin (tan^ 1x)1 + x^2 dx Substitute #160; tan^ 1x=u ⇒11+x^2dx=du Therefore #160; I=∫sin u du= cos u+C= cos(tan^ 1x)+C ...

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Trigonometric Identities

Find : ∫sin...

Question

Find : $\int \frac{sin ({tan}^{- 1} x)}{1 + x^{2}} d x, x ϵ R$

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