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Question

Find:
xex(1+x)2dx

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Solution

y=xex(1+x)2dx
y=[11+x1(1+x)2]dx
We know ex[f(x)f(x)]=exf(x)
then
y=ex[11+x1(1+x)2]dx=ex1+x+c

1212968_1365828_ans_3df70d4bb4c2431dbe5b8392c7b6c920.JPG

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